Answer:
so x=5y

reciprocal of x=1/x then

sum of reciprocals means 1/x+1/y=2/5

subsitute x=5y for x in 1/x+1/y=2/5 and get

1/5y+1/y=2/5

multiply 1/y by 5/5 to make it 5/5y so you can add since the denomenators (bottom number) are the same

1/5y+5/5y=2/5

6/5y=2/5

multiply both sides by 5y

6=2y

divide both sides by 2

3=y

put this into x=5y so

x=5(3)

x=15

y=3

reciprocal of x=1/x then

sum of reciprocals means 1/x+1/y=2/5

subsitute x=5y for x in 1/x+1/y=2/5 and get

1/5y+1/y=2/5

multiply 1/y by 5/5 to make it 5/5y so you can add since the denomenators (bottom number) are the same

1/5y+5/5y=2/5

6/5y=2/5

multiply both sides by 5y

6=2y

divide both sides by 2

3=y

put this into x=5y so

x=5(3)

x=15

y=3

Find the upper bonds for the following lengths : a) 40cm measured to the nearest cmB)82.8cm measured to the nearest tenth of a cm

Please help me!when it ask me to Multiply your sum by the cube of 25.does that mean i have to put 25 to the second power or square root it

Two times x divide five

Julia worked 45 hours last week. If her earning rate is $6.50 for straight time (40 hours) and she earns time-and-a-half rate for all hours over 40, how much did she earn last week?

Q6.2(8 + 2 x 6)2 =the two at the end of the brackets is squared it a small two

Please help me!when it ask me to Multiply your sum by the cube of 25.does that mean i have to put 25 to the second power or square root it

Two times x divide five

Julia worked 45 hours last week. If her earning rate is $6.50 for straight time (40 hours) and she earns time-and-a-half rate for all hours over 40, how much did she earn last week?

Q6.2(8 + 2 x 6)2 =the two at the end of the brackets is squared it a small two

b. 5P5 × 20P15

c. 5C5 × 25C14

d. 5P5 × 15P15

e. 5P5 × 25C15

**Answer:**

The correct option is b.

**Step-by-step explanation:**

It is given that the school bus has 25 seats, with 5 rows of 5 seats.

The number of students from the first grade is 15 and the number students from the second grade is 5.

The formula to arrange r items in n places is

The number of seats in first row is 5 and the number students from the second grade is 5. So, the total number of arrangement is

The number of seats except first row is 20 and the number students from the first grade is 15. So, the total number of arrangement is

The total number of ways the students can be seated if all of the second-grade students occupy the first row is

**Therefore the correct option is b.**

Answer:

b

Step-by-step explanation:

plato fam

it's 12x24=288 problem solved

Given:

Original or base : 40

New amount : 72

We need to find the difference of the new amount and the original amount

72 - 40 = 32

We then divide the difference by the original amount

32/40 = 0.80

We multiply the quotient by 100%

0.80 x 100% = 80%

**The percentage of change is 80%**

Original or base : 40

New amount : 72

We need to find the difference of the new amount and the original amount

72 - 40 = 32

We then divide the difference by the original amount

32/40 = 0.80

We multiply the quotient by 100%

0.80 x 100% = 80%

3. find the value of x,

3a. sin(x) = cos 31,

3b. sin 75 = cos(x),

3c. sin(x-4) = cos 50

**Step-by-step explanation:**

Answer:

\frac{7}{4}

4

7

Explanation:

______________________

We know the values of

i) cos0° = 1

ii) sin45° = \frac{1}{\sqrt{2}}

2

1

iii) sin30° = \frac{1}{2}

2

1

iv) sin90° = 0

v) cos45° = \frac{1}{\sqrt{2}}

2

1

vi ) cos60° = \frac{1}{2}

2

1

_____________________

Now,

The value of

(cos 0+sin 45+sin 30)(sin 90-cos 45+cos 60)

= \left(1+\frac{1}{\sqrt{2}}+\frac{1}{2}\right)\left(1-\frac{1}{\sqrt{2}}+\frac{1}{2}\right)(1+

2

1

+

2

1

)(1−

2

1

+

2

1

)

= \left(\frac{3}{2}+\frac{1}{\sqrt{2}}\right)\left(\frac{3}{2}-\frac{1}{\sqrt{2}}\right)(

2

3

+

2

1

)(

2

3

−

2

1

)

= \left(\frac{3}{2}\right)^{2}-\left(\frac{1}{\sqrt{2}}\right)^{2}(

2

3

)

2

−(

2

1

)

2

/* By algebraic identity

(a-b)(a+b) = a²-b² */

= \left( \frac{9}{4}-\frac{1}{2}\right)(

4

9

−

2

1

)

= \frac{9-2}{4}

4

9−2

= \frac{7}{4}

4

7

••••

**Answer:**

In this geometric series, a represents the first term, what he pays back monthly is the common ratio which is 1.2, and the first 30 payments are what is being used to find the total amount which is represented by n. Thus, a=$200, n=30 and r=1.2. The sum is found by sn=(a((r^n)-1))/(r-1), which will be 200((1.2^30)-1))/(1.2-1). The solution is = $ 236,376 and the series is divergent because of the common ratio being greater than 1.

**Step-by-step explanation:**

This is a geometric series. The first payment represents the first term, a. The number of times he wants to pay back for subsequent payments represent the common ration, r. The first 30 payments represents the number of terms to use in finding the sum, n.

Hence, a = $ 200, n = 30 and r = 1.2.

The sum of a geometric sequence is given as:

Sn = (a((r^n)-1))/(r-1)

=(200((1.2^30)-1))/(1.2-1)

= $ 236, 376. 31

Explain why this series is convergent or divergent.

Since the common ratio, r, is greater than 1, the series is divergent

Hence, a = $ 200, n = 30 and r = 1.2.

The sum of a geometric sequence is given as:

Sn = (a((r^n)-1))/(r-1)

=(200((1.2^30)-1))/(1.2-1)

= $ 236, 376. 31

Explain why this series is convergent or divergent.

Since the common ratio, r, is greater than 1, the series is divergent

**Answer:**

**Step-by-step explanation:**

Rationale: Amount accrued: $32,000 x 7/10 = $22,400

Because we know:

- The current pay period ends on Friday, July 3

- Neat Clothes is now preparing quarterly financial statements for the three months ended June 30

From Friday, June 30 to July 3 is 10 days