# a Pontiac trans-am, initially at rest accelerates at a constant rate of 4.0 m/s squared for six seconds how fast will the car be traveling a T equals six seconds

rearrange: Vf=at
solve: Vf= 4.0m/s squared x 6s
Vf = 24 m/s --> sigdigs
Vf = 2.4 x 10^1 m/s

## Related Questions

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What is the definition of law of conservation of energy￼

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside. This is particularly confusing in the case of non-conservative forces, where energy is converted from mechanical energy into thermal energy, but the overall energy does remain the same. The only way to use energy is to transform energy from one form to another.

Explanation:

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means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.

Explanation: this is a shorter answer.

A 5.0 g lead bullet is fired into a fence post. The initial speed of the bullet is 210 m/s, and when it comes to rest, half its kinetic energy goes into heating the bullet. How much does the bullet's temperature increase?

Given the data from the question, the bullet's temperature increases by 85.5 °C

### How to determine the kinetic energy

• Mass (m) = 5 g = 5 / 1000 = 0.005 g
• Velocity (v) = 210 m/s
• Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.005 × 210²

KE = 110.25 J

### How to determine the increase in temperature

• Kinetic energy (KE) = 110.25 J
• Heat (Q) = ½KE = ½ × 110.25 = 55.125 J
• Mass (M) = 5 g
• Specific heat capacity of lead (C) = 0.129 J/gºC
• Change in temperature (ΔT) =?

Q = MCΔT

Divide both side by MC

ΔT = Q / MC

ΔT = 55.125 / (5 × 0.129)

ΔT = 85.5 °C

Thus, the temperature increase is 85.5 °C

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5g = 0.005 kg
So KE=1/2 0.005 kg * 210m/s^2 = 110 J.
Now the specific heat capacity of lead is 126 J/kgK, so the temperature change= 55 J / 0.005 * 126 J/kgK=87.3015873 K. Which, if normal thermal conditions, the bullet would have a temperature of around 360,451587 Kelvin or, simplified, 107.3 degrees celsius.

The acceleration of gravity is a constant equal to _______ meters per second squared.A. 9.8
B. 8.4
C. 10.2
D. 7.6

The acceleration due to gravityis the acceleration on an object caused by force of gravitation. It means thatthe earth has a gravitational field that projects all bodies on earth towards itscenter. The gravity of an object or body of an object is high on earth than atthe atmosphere. It has an average of gravitational constant equal to 9.8066 or9.8 meters per second. In truth, the acceleration of the object depend upon itslocation, the latitude and altitude, on earth.

A. 9.8

Explanation:

a piano of mass 852 kg is lifted to height of 3.5m how much gravitational potential energy is added to the piano acceleration due to the gravity is g=9.8 m/s2

(mass) x (gravity) x (distance lifted)

=  (852 kg) x (9.8 m/s²) x (3.5 m)

=  (852 x 9.8 x 3.5)  kg-m²/s²

=        29,223.6  joules

The motion graph shown below was created by a toy train which starts out moving north. The train starts from a position of 2.0m north.

The motion graph provided represents the displacement of a toy train over time. The graph consists of two distinct segments: an initial period of constant velocity followed by a period of rest.

From the given information, we can determine that the train starts from a position of 2.0m north. This means that at t=0 (the beginning of the graph), the train is located 2.0m north of its starting point.

The first segment of the graph shows a straight line with a positive slope, indicating constant velocity. Since the train is moving north, the positive slope suggests that it is moving in the positive direction along the y-axis. The steeper the slope, the greater the velocity.

The second segment of the graph shows a horizontal line, indicating that the train is at rest. During this period, the train does not undergo any displacement and remains stationary.

To determine the total displacement of the train, we need to calculate the area under the graph. In this case, we have two separate areas to consider: one for each segment.

For the first segment, which represents motion, we can calculate the area by finding the area of a triangle. The formula for calculating the area of a triangle is A = 1/2 * base * height. In this case, the base corresponds to the time interval and the height corresponds to the displacement.

Let's assume that each unit on both axes represents 1 second and 1 meter, respectively. From the graph, we can estimate that the time interval for the first segment is approximately 4 seconds and that the displacement is approximately 8 meters (from t=0 to t=4). Therefore, using our formula, we can calculate:

A = 1/2 * 4s * 8m = 16m²

So, during this period of motion, the train has a displacement of 16 meters.

For the second segment, which represents rest, the train does not undergo any displacement. Therefore, the area under the graph is zero.

To calculate the total displacement of the train, we sum up the areas from both segments:

Total displacement = 16m² + 0m² = 16m²

Hence, the total displacement of the toy train is 16 meters.

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When 10 N force applied at 30 degrees to the end of a 20 cm handle of a wrench, it was just able to loosen the nut. What magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle

## 5N

Explanation:

To get the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle, we will have to resolve the force perpendicular to the wrench. Torque is the turning effect of a body or force about a point. It is similar to moments.

Note that the force must be perpendicular to the wrench. On resolving the force perpendicularly to the wrench, we will have to resolve the force to the vertical.

Fy = Fsinθ

Fy = 10sin30°

Fy = 10 * 0.5

Fy = 5N

Torque = Fy * r

Given Fy = 5N and r = 20cm = 0.2m

Torque = 5 * 0.2

Torque = 1Nm

Hence the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle is 5N